4t^2-1t-1=0

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Solution for 4t^2-1t-1=0 equation:



4t^2-1t-1=0
a = 4; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·4·(-1)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{17}}{2*4}=\frac{1-\sqrt{17}}{8} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{17}}{2*4}=\frac{1+\sqrt{17}}{8} $

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